Derivatives of Exponentials I

$\frac{d}{d x} e^{8 x - 2}$

=

$\frac{d}{d x} e^{u}$

=

$\frac{d}{d u} (e^{u}) \frac{d u}{d x}$

=

$e^{u} (8)$

=

$e^{8 x - 2} (8)$

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