Derivatives of Exponentials I

\frac{d}{d x} e^{4 x^{3} - 8 x^{2} + 9 x + 2}

=

\frac{d}{d x} e^{u}

=

\frac{d}{d u} (e^{u}) \frac{d u}{d x}

=

e^{u} (12 x^{2} - 16 x + 9)

=

e^{4 x^{3} - 8 x^{2} + 9 x + 2} (12 x^{2} - 16 x + 9)

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Copyright © Dayal D. Purohit, Ph.D.(Mathematics)