Integral using Substitution (Polynomials and Rationals)
I =
∫
(
6
x
+
2
)
(
6
)
d
x
Put
u
=
6
x
+
2
, then
d
u
=
(
6
)
d
x
or,
d
u
=
(
6
)
d
x
I =
∫
(
u
)
d
u
I =
∫
(
u
)
d
u
I =
(
u
)
2
2
+
C
I =
(
6
x
+
2
)
2
2
+
C
Algebra
Analytic Geometry
Differential Calculus
Integral Calculus
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Copyright © Dayal D. Purohit, Ph.D.(Mathematics)