Solving Quadratic Equations using Quadratic Formula

   If  $a{x}^2+bx+c$ = 0, then $x$ =  $\frac{\mathrm{-b}\pm \sqrt{b^2-\mathrm{4ac}}}{\mathrm{2a}}$

So, if  $6x^2+40x+24$ = 0, then

     $x$ =  $\frac{-(40)\pm \sqrt{{(\mathrm{40})}^2-(4)(6)(24)}}{(2)(6)}$

or, $x$ =  $\frac{\mathrm{-40}\pm \sqrt{1600-576}}{\mathrm{12}}$

or, $x$ =  $\frac{\mathrm{-40}\pm \sqrt{1024}}{\mathrm{12}}$

or, $x$ =  $\frac{\mathrm{-40}\pm 32}{\mathrm{12}}$

or,  $x$ =  $\frac{-8}{12}$ or,  $x$ =  $\frac{-72}{12}$

or,  $x$ =  $\frac{-2}{3}$ or,  $x$ =  $-6$